Find out the compounds that would get formed when heating copper carbonate

The saturation of CuO and Cu2O are black and red respectively. rut squealer speed of lightate strongly allow for produce pig (ll) oxide and carbon dioxide that will be addicted eat up so basically the equality that results from this isCuCO3 (s) ? CuO (s) + carbon dioxide (g).By high temperature for about 3g of the green powder of cop carbonate, I should obtain a new compound with the black colour proving the presence of copper (ll) oxide.The quite a little of the carbon dioxide that will result from heating copper carbonate depends on the push-down stack of copper carbonate. Actually, it is proportional to it the big the mass of copper carbonate the big the volume of gas given off and the bigger the mass of the product formed. The snip of heating is actually important as easily because the copper carbonate isnt completely burnt, it will affect the quantity of gas and the mass of the compound formed.In the advance experiment, I just identified which compound that w as formed knowing the colours. employ the same apparatus as in the proper experiment, I alter 1.00gram of a green powder of copper carbonate and obtained 0.30gram of copper (ll) oxide. That experiment was limited in the fact that I couldnt measure directly the volume of gas that was given of in the reaction and, considering the accuracy of the chemical dimension used, that mass used was small providing an error of ? 1% in the mass of copper carbonate. So, to improve this I used a much bigger mass in the proper experiment for the accuracy of the balance couldnt be improved.* Crucible and lid.* Pipe clay triangle.* Tripod.* Heatproof mat.* Bunsen burner.* Tongs* Chemical balance.* fleeceable powder of copper carbonate.* Bell jar.(Eye protection required WEAR guard GOGGLES?TAKE CARE TO AVOID BURNS.WEIGH (to the nearest 0.01g) EVERYTHING doubly AT LEAST TO AVOID ERRORS.1. Set the tripod, Bunsen burner (switched off), heatproof mat and squall clay triangle as above.2. Weigh the c rucible and lid and account book the measurement.3. Letting the crucible on the balance, add the powder of copper carbonate for a little more than 3.00g.4. Put the lid back and eternise the measurement.5. Place the set onto the organ pipe clay triangle.6. Switch the Bunsen burner on and heat the crucible strongly.7. Using the tongs, lift the lid slightly from time to time to check whether the colour of the copper carbonate has completely changed or not.8. When the colour has changed totally (after about 10 minutes), switch the Bunsen burner off and remove the crucible and lid development tongs form the pipe clay triangle.9. Allow it to cool into a Bell jar.10. Re-weigh the crucible and lid and copper (ll) oxide formed in and record the measurement.11. Range the apparatus back. multitude of crucible + lid = 17.86gMass of crucible + lid + copper carbonate = 21.58gMass of copper carbonate = 3.72gMass of crucible + lid + copper oxide formed = 20.45gCuCO3 (s) ? CuO (s) + CO2 (g).n Cu CO3 (s) = n CO2 (g).M CuCO3 (s) = V CO2 (g).Mr VmMr = 63.5 + 12 + 3 x 16 = 123.5 gmol-1M CuCO3 (s) = 3.72 gVm = 24 dm-33.72 g = V CO2 (g).123.5 gmol-1 24 dm-3So V CO2 (g) = 0.723 dm-3M CuO (s) = Mass of (crucible + lid + copper oxide formed) Mass of (crucible + lid) soM CuO (s) = 2.59g.If my method and my results are right so the volume of CO2 given up was 0.723 dm-3 and the mass of CuO obtain was 2.59g.This method could only alter us to calculate the volume. The total uncertainties in that volume is the same of ace of the mass of copper oxide formed for they depend quantitatively to the mass of copper carbonate used. The chemical balance was accurate to 0.01g.That error is ?(0.01/3.72) x 100 ? 0.27% then the order of proportionality of the results are V CO2 (g) = (0.723 ? 0.0027) dm-3 and M CuO (s) = (2.59 ? 0.0027) g.If I had to repeat this experiment, I would use a gas inch well greased (to enable the pressure of gas to push it) by which I can just measure the volume of gas d irectly using a similar mass.